The length of the rectangle is 70 cm and its width is 70% of the length, find the perimeter and area of the rectangle.

1. The condition of the problem is a rectangle.

It is known that the length of the figure is 70 cm.

The width of the rectangle is not explicitly set, but it is said to be 70% or 70/100 = 7/10 of the length.

Let’s calculate the width.

70 * 7/10 = 49 cm.

2. Now you can calculate the area of the given rectangle.

It is determined by the product of its length and width.

S = 70 * 49 = 3430 cm2.

3. Find the perimeter of the shape.

It is found by doubling the sum of the length and width.

P = 2 * (70 + 49) = 2 * 119 = 238 cm.

Answer: The area of the rectangle is 3430 cm2, the perimeter is 238 cm.



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