The length of the rectangle is 720 m and the width is 80 m less. Find the area of the rectangle and its perimeter.

Given:
The length a of the rectangle is 720 meters.
The width b of the quadrangle is 80 meters less than the length a.

Let’s find what the width b is equal to:
b = a – 80 = 720 – 80 = 640 meters.
The perimeter of this figure is calculated by the formula P = a + a + b + b:
P = a + a + b + b = 720 + 720 + 640 + 640 = 2720 meters.
The area of this figure is calculated by the formula S = a * b:
S = a * b = 720 * 640 = 460800 m2.
Answer: the perimeter of the figure is 2,720 meters, and the area is 460,800 m2.