# The length of the rectangle is 720 m and the width is 80 m less. Find the area of the rectangle and its perimeter.

May 31, 2021 | education

| Given:

The length a of the rectangle is 720 meters.

The width b of the quadrangle is 80 meters less than the length a.

Let’s find what the width b is equal to:

b = a – 80 = 720 – 80 = 640 meters.

The perimeter of this figure is calculated by the formula P = a + a + b + b:

P = a + a + b + b = 720 + 720 + 640 + 640 = 2720 meters.

The area of this figure is calculated by the formula S = a * b:

S = a * b = 720 * 640 = 460800 m2.

Answer: the perimeter of the figure is 2,720 meters, and the area is 460,800 m2.

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