The length of the rectangle is 7dm, the width is 4dm, the length of the side of the square is 70cm

univerkov | June 25, 2021 | education

The length of the rectangle is 7dm, the width is 4dm, the length of the side of the square is 70cm. Whose perimeter is greater?

1. The length of the rectangle is 7 dm = 70 cm.

2. The width of the rectangle is 4 dm = 40 cm.

3. Calculate the perimeter of the rectangle.

70 + 70 + 40 + 40 = 220 cm.

4. Next, we find the perimeter of the square.

70 + 70 + 70 + 70 = 70 * 4 = 280 cm.

5. Since 280> 220, therefore the perimeter of the square is greater than the perimeter of the given rectangle.

Answer: The perimeter of the square is greater than the perimeter of the rectangle.

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