The length of the rectangle is 8.1 cm, and the width of the rectangle is 90% of its length.

The length of the rectangle is 8.1 cm, and the width of the rectangle is 90% of its length. What is the area of a square with the same perimeter as this rectangle?

1) Calculate the width of the rectangle. To do this, we divide its length by 100% and multiply by 90%:

8.1: 100 * 90 = 7.29 cm.

2) Define the perimeter of the rectangle (Pпр) as the sum of the lengths of all its sides:

Ppr = 8.1 + 7.29 + 8.1 + 7.29 = 30.78 cm.

3) By the condition of the problem, the perimeter of the square (Pкв) is equal to the perimeter of the rectangle:

Pкв = Рпр = 30.78 cm.

4) Find out what the side of the square is equal to:

30.78: 4 = 7.695 cm.

5) Calculate the area of the square:

Skv = 7.695 ^ 2 = 59.21 cm ^ 2.

Answer: The area of the square is 59.21 cm ^ 2.



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