The length of the rectangle is 8 cm longer than the width. Find the perimeter and area if the width is 2/3 of the length

1. Let the length of the rectangle be x, then we express the width of the rectangle, according to the condition of the problem:
Width = x * 2/3 or x – 8.
2. Equate both length expressions and find x:
x * 2/3 = x – 8,
2x = 3 * (x – 8),
2x = 3x – 24,
24 = 3x – 2x,
24 = x,
x = 24.
3. Find the width of the rectangle:
24 – 8 = 16 cm.
4. Find the perimeter of the rectangle by adding twice the value of its length and width:
Perimeter = 2 * 16 + 2 * 24 = 32 + 48 = 80 cm.
5. Find the area of the rectangle by multiplying the length by the width:
Area = 16 * 24 = 384 cm2.
Answer: the perimeter of the rectangle is 80 cm, and its area is 384 cm2.