The length of the rectangle is 8 cm longer than the width. Find the perimeter and area of the rectangle

The length of the rectangle is 8 cm longer than the width. Find the perimeter and area of the rectangle if the width is 2/3 of the length.

Let’s solve this problem using the equation.

Let the length of the rectangle be x centimeters, then the width of the rectangle is 2/3 * x centimeters. We know that the length of the rectangle is 8 centimeters longer than the width. we compose the equation:

x – 2/3 * x = 80;

x * (1 – 2/3) = 80;

x * (3/3 – 2/3) = 80;

x * 1/3 = 80;

x = 80: 1/3;

x = 80 * 3;

x = 240 centimeters – the length of the rectangle;

240 * 2/3 = (240 * 2) / 3 = (80 * 2) / 1 = 160 centimeters – the width of the rectangle;

2 * (240 + 160) = 2 * 400 = 800 centimeters – the perimeter of the rectangle;

240 * 160 = 38 400 cm ^ 2 – the area of the rectangle.

Answer: 800 centimeters; 38,400 cm ^ 2.