The length of the rectangle is 8 cm, the perimeter is 24 cm. Find its area

The perimeter P of a rectangle is the sum of all its sides or the sum of its two lengths (a) and its two widths (b), P = 2a + 2b, from here we find the width of the rectangle
в = (Р-2а) / 2, we substitute the values from the condition
in = (24-2 * 8) / 2 = (24-16) / 2 = 8/2 = 4 (see)
The area S of a rectangle is equal to the product of its length and width, S = a * b
find it:
S = 8 * 4 = 32 (cm squared)
Answer: 32 cm squared.