The length of the rectangle is 8dm, which is 3dm longer than its width. How much will the area increase
The length of the rectangle is 8dm, which is 3dm longer than its width. How much will the area increase if the length is doubled?
First, let’s find how many decimeters the width of this rectangular quadrangle is.
In the initial data for this task, it is reported that the length of this quadrangle with four right angles is eight decimeters, which is three decimeters more than its width, therefore, the width of this rectangular quadrangle is 8 – 3 = 5 dm, and its area is 8 * 5 = 40 dm ^ 2.
If the length of this quadrangle is doubled, then the length of the resulting quadrangle will be 2 * 8 = 16 dm, and the area of the resulting quadrangle will be 16 * 5 = 80 dm ^ 2, which is 80 – 40 = 40 dm ^ 2 more than the area of the original quadrilateral.
Answer: 40 dm ^ 2.