The length of the rectangle was increased by 60%, and the width was decreased by 60%.

The length of the rectangle was increased by 60%, and the width was decreased by 60%. How did the area of the rectangle change and by what percentage?

Let us have a rectangle with sides: length – a and width – b. The area of the rectangle is: S = a * b. If the length of the rectangle is increased by 60%, then we get the value of the length: a1 = a + 0.6a = 1.6a. If the width of the rectangle is reduced by 60%, then we get the width value: B1 = B – 0.6B = 0.4B. The area of the new rectangle is: S1 = a1 * b1 = 1.6 * a * 0.4 * b = 0.64 * a * b. It follows from this that if the length of the rectangle is increased by 60% and the width is reduced by 60%, then its area will decrease by 36%.