The length of the rectangular parallelepiped is 12 cm, the width is 2 times less than the length, and the height is 2 cm

The length of the rectangular parallelepiped is 12 cm, the width is 2 times less than the length, and the height is 2 cm less than the length. Find the sum of the areas of all the faces of the rectangular parallelepiped.

First, let’s find all the edges:

By condition, 12 (cm) is the length.

12: 2 = 6 (cm) – width.

12 – 2 = 10 (cm) – height.

The parallelepiped has 6 faces in total:

The first two faces: width * height = 6 * 10 = 60 cm2. There are two of them:

60 * 2 = 120 (cm2) – face area (height / width).

Now the edges: width by length = 6 * 12 = 72 cm2. 72 * = 144 (cm2) – face area (width / length).

Further: length to height = 12 * 10 = 120 (cm2). 120 * 2 = 240 (cm2) – face area (length \ height).

We summarize: 120 + 144 + 240 = 504 (cm2).

Answer: 504 cm2.