The length of the rectangular park is 20 m longer than its width. The sum of the length and width is 46

The length of the rectangular park is 20 m longer than its width. The sum of the length and width is 46 m. Gabil runs along the sides of the park 4 times every morning. How many meters does Gabil run every morning?

Let’s denote the width through x, then the length is equal to x + 20. Next, we find the length and width of the park. We write down the solution.
X + x + 20 = 46.
2x + 20 = 46.
2x = 46 – 20.
2x = 26.
X = 26: 2 = 13.
This means that the width is 13 m.
13 + 20 = 33 m.
The length is 33 meters.
Next, we find the perimeter of the park. We write down the solution.
P = 2 * (13 + 23) = 2 * 46 = 92 m.
Since Gabil every morning they come running around the park 4 times. So, we multiply the perimeter by 4.
4 * R = 4 * 92 = 368 m.
This means that Gabil runs 368 meters around the park every morning.
Answer: 368 m.



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