The length of the rectangular piece of land is 43 m and its width is 15 m less than the length. Find the perimeter and area of the lot.

Since the length of a rectangular piece of land is 43 m, and its width is 15 m less than the length, then the width is 43 m – 15 m = 28 m. Since the piece of land has a rectangular shape, we will consider it a rectangle. The perimeter of a rectangle is the sum of all its sides. Since the opposite sides of the rectangle are equal, then P = 2 * a + 2 * b. Substituting the known values of the sides 43 m and 28 m, we find the value of the perimeter: P = 2 * 43 + 2 * 28 = 86 + 54 = 140 m. The area of the rectangle is equal to the product of length and width: S = a * b, S = 43 * 28 = 1204 m2.