The length of the rectangular section is 48 meters, the width is 2 times less. Find the perimeter of the lot.

Let’s find the width of this rectangular area.
According to the condition of the problem, the length of this rectangular section is 48 meters, and its width is 2 times less than the length, therefore, the width of this rectangular section is:
48/2 = 24 m.
Let us find the perimeter P of a given rectangular section as the doubled sum of the length and width of this section:
P = 2 * (48 + 24) = 2 * 72 = 144 m.
Answer: the perimeter of this rectangular section is 144 m.