The length of the second hand is 10cm. Find the speed at the end of the arrow.

Initial data: L (length of the second hand) = 10 cm (0.1 m) = R (radius of the circle that the second hand will describe).

1) Determine the path (circumference) that the second hand will pass in 1 minute (t = 60 s): S = 2 * Π * R = 2 * 3.14 * 0.1 = 0.628 m.

2) Let’s calculate the speed of the arrow end: V = S / t = 0.628 / 60 ≈ 0.01 m / s.

Answer: d) the speed of the end of the second hand is 0.01 m / s.



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