The length of the side of the rectangle is 14 cm, the length of the side of the square is 10 cm.

| February 6, 2021 | education

The length of the side of the rectangle is 14 cm, the length of the side of the square is 10 cm. What are their areas if it is known that their perimeters are the same?

Condition

l = 14 cm

length of sides square = 10 cm

S find the areas of a square and a rectangle

decision

First, we will find the area of ​​a square to immediately solve half of the problem

The area of ​​a square is equal to its side in the square te 10 * 10 = 100 cm2

2) Find the perimeter of the square This is the sum of all its sides at the square 4 sides

p = 10 * 4 = 40 cm

Tk the perimeter of the square is equal to the perimeter of the rectangle

40 cm then it turns out 2 sides of the rectangle + 2 sides of the rectangle is 40 cm

mk one side of the rectangle is 14 cm, then 2 are the same sides and 2 other widths are equal between the slab, then from 40 we subtract 14 * 2 40-28 = 12 the length of its 2 other sides

1 side is 12: 2 = 6 cm

The area of ​​the rectangle is one side by width

14 * 6 = 84 cm2

Answer 84 cm2; 100 cm2



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