The length of the side of the square is 4 cm, the width of the rectangle is 2 cm.

The length of the side of the square is 4 cm, the width of the rectangle is 2 cm. Compare the area of the rectangle and the square if the perimeter of the rectangle is 24 cm.

The task:
side length of the square – 4 cm
the length of the rectangle -?,
width of the rectangle – 2 cm,
perimeter of the rectangle – 24 cm,
compare the areas of a rectangle and a square.
Decision:
1) define the length of the rectangle:
(24 – 2 2): 2 = (24 – 4): 2 = 20: 2 = 10 cm;
2) calculate the area of the rectangle:
10 2 = 20 cm ^ 2;
3) calculate the area of the square:
4 4 = 16 cm ^ 2;
4) let’s compare the areas:
20 – 16 = 4 cm ^ 2.
Answer: the area of the rectangle is larger than the area of the square by 4 cm ^ 2.