The length of the sides of one rectangle is 8cm and 3cm, and the other is 4cm and 3cm. how many times

The length of the sides of one rectangle is 8cm and 3cm, and the other is 4cm and 3cm. how many times is the area of one rectangle larger than the area of another? How much is the area of one rectangle larger than the area of the other? what is the pyrimeter of each rectangle? Which rectangle has a pyrimeter larger and by how much? what is the area of two rectangles?

1. Find the area of ​​rectangles by the formula S = a * b, multiplying their sides:

S1 = a1 * b1;

S1 = 8 * 3 = 24 cm2.

S2 = a2 * b2;

S2 = 4 * 3 = 12 cm2.

2. Determine how many times the area of ​​one rectangle is greater than the area of ​​another. To do this, divide the area of ​​the larger rectangle by the area of ​​the smaller one:

S1: S2 = 24: 12 = 2 times.

3. Let’s calculate how much the area of ​​one rectangle is larger than the area of ​​another. To do this, subtract the area of ​​the smaller rectangle from the area of ​​the larger rectangle:

S1 – S2 = 24 – 12 = 12 cm2.

4. Find the perimeter of each rectangle using the formula P = 2 * (a + b).

P1 = 2 * (a1 + b1);

P1 = 2 * (8 + 3) = 2 * 11 = 22 cm.

P2 = 2 * (a2 + b2);

P2 = 2 * (4 + 3) = 2 * 7 = 14 cm.

5. Let’s compare the perimeters.

22 cm> 14 cm;

P1> P2.

6. Determine how much the perimeter of the first rectangle is greater than the perimeter of the second rectangle. To do this, subtract the perimeter of the smaller rectangle from the perimeter of the larger rectangle:

P1 – P2 = 22 – 14 = 8 cm.

7. Find the area of ​​two rectangles. To do this, add the area of ​​the first rectangle and the area of ​​the second:

S1 + S2 = 24 + 12 = 36 cm2.