The length of the sports field is 25m, and the width is 5m less. Sports facilities occupy two-fifths

The length of the sports field is 25m, and the width is 5m less. Sports facilities occupy two-fifths of the area. What is the area occupied by sports facilities.

In order to solve this problem, you need to know the formula for finding a rectangle (the sports ground has a rectangular shape).
S = a • b, where S is the area of the rectangle, a is the side length, b is the side width.
But we need to find 2/5 of this area, then the formula will look like this:
2/5 S = 2/5 a • b.
By the condition of the problem, the length “a” is equal to 25 m, and the width “b” is 5 m less, that is, b = a – 5 = 25 – 5 = 20 m.
Now let’s substitute the received data into the formula:
2/5 S = 2/5 • 20 • 25 = 200 m ^ 2.
Answer: 2/5 S = 200 m ^ 2.