The length of the spring is 13 cm, a body weighing 18 Newtons is suspended, find the stiffness
| April 9, 2021 | education
The length of the spring is 13 cm, a body weighing 18 Newtons is suspended, find the stiffness of the spring if the length is 16 cm.
Initial conditions: P (weight of the body suspended from the spring) = 18 N; l1 (initial length of the spring) = 13 cm; l2 (spring length after stretching) = 16 cm.
SI system: l1 = 13 cm = 13/100 = 0.13 m; l2 = 16 cm = 16/100 = 0.16 m.
1) Calculate the amount of spring deformation:
Δl = l2 – l1 = 0.16 – 0.13 = 0.03 m.
2) Calculate the stiffness coefficient (we use Hooke’s law):
Fcont. = Р = k * Δl.
k = P / Δl = 18 / 0.03 = 600 N / m.
Answer: The spring stiffness (stiffness coefficient) is 600 N / m.
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