The length of the triangle is 2 and 2 more than its width and the width is 8.6 cm.

univerkov | May 14, 2021 | education

The length of the triangle is 2 and 2 more than its width and the width is 8.6 cm. Find the perimeter and area of the rectangle.

Let’s find the length of the given rectangle.
According to the condition of the problem, the length of this rectangle is 2.2 more than its width, and the width of this rectangle is 8.6 cm, therefore, the length of this rectangle is:
8.6 + 2.2 = 10.8 cm.
Let’s find the perimeter of this rectangle. The perimeter of a rectangle is equal to twice the sum of the length and width of this rectangle, therefore, the perimeter of this rectangle is:
2 * (8.6 + 10.8) = 2 * 19.4 = 38.8 cm.
Let’s find the area of this rectangle. The area of the rectangle is equal to the product of the sides of the rectangle, therefore, the area of this rectangle is:
8.6 * 10.8 = 92.88 cm².
Answer: the perimeter of this rectangle is 38.8 cm, the area of this rectangle is 92.88 cm².

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