The lever arm is in equilibrium equal to 40cm and 30cm a force of 120N is applied

The lever arm is in equilibrium equal to 40cm and 30cm a force of 120N is applied to the smaller arm, which force is applied to the large arm

As we know from the school physics course, the equilibrium position of the lever can be described in the form of the following formula:

F1 / F2 = l2 / l1.

Let us determine what the value of the force will be, the shortening one acts on the arm of the lever 40 centimeters long, when from the condition of our problem it is precisely known that a force of 120 N acts on the other arm 30 centimeters long:

F1 = F2 * l2 / l1;

120 * 30: 40 = 3600: 40 = 90.

Answer: Under these initial conditions, a force of 90 N will act on the 40 cm arm of the lever.