The lever is acted upon by a force equal to 3 N. What is the moment of this force if the shoulder of the force is 15 cm?

Given:

F = 3 Newton – the force that acts on the lever;

dx = 15 centimeters is the shoulder length of this force.

It is required to determine p (N * m) – the moment of force F.

We translate the units of measurement of length into the SI system:

dx = 15 cm = 15 * 10 ^ -2 = 15/100 = 0.15 meters.

Then, to determine the moment of force, you must use the following formula:

p = F * dx = 3 * 0.15 = 0.45 N * m (Newton per meter).

Answer: the moment of force F is equal to 0.45 N * m.