The lever is balanced by two forces. Force f1 = 12H. The length of the lever is 50 cm, the arm of force f1 is 30 cm. What is the force of f2?
| December 3, 2020 | education
Given: F1 = 12H L = 50cm = 0.5m l1 = 30cm = 0.3m
Find: F2-?
Solution: F1 * l1 = F2 * l2 => F2 = F1 * l1 / l2 L = l1 + l2 => l2 = L – l1 = 0.5 – 0.3 = 0.2 (m) F2 = 12 * 0 .5 / 0.3 = 20 (H)
Answer: F2 = 20H.
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