The lever is balanced by two forces. The first force 4 H has a shoulder of 15 cm.
| August 9, 2021 | education
The lever is balanced by two forces. The first force 4 H has a shoulder of 15 cm. Determine what the second force is equal to if her shoulder is 10 cm.
F1 = 4 N.
r1 = 15 cm = 0.15 m.
r2 = 10 cm = 0.10 m.
F2 -?
When the lever is in equilibrium, the moments of forces that act from opposite sides of the lever are equal to each other: M1 = M2.
The moment of force M is called the product of the applied force F to the smallest distance from the application of force to the axis of rotation of the lever, which is called the arm r: M = F * r.
The equilibrium condition will take the form: F1 * r1 = F2 * r2.
F2 = F1 * r1 / r2.
F2 = 4 N * 0.15 m / 0.1 m = 6 N.
Answer: a force F2 = 6 N. acts on the opposite side of the lever.
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