The lever, under the action of the forces applied to it, is in equilibrium. What is the shoulder of the force F1 = 3H

The lever, under the action of the forces applied to it, is in equilibrium. What is the shoulder of the force F1 = 3H if the moment of force F2 is 0.6H · m?

Given:
The lever, under the action of the forces applied to it, is in equilibrium. arm of force F1 = 3H, if moment of force F2
equals 0.6H m
M1 = M2 = 0.6N * m
M1 = F1 * l1
l1 = M1: F1
l1 = 0.6: 3 = 0.2 m
Answer: l1 = 0.2 meters.



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