The lift moves upward with an acceleration of 1 m / s2. The force of the body pressure

The lift moves upward with an acceleration of 1 m / s2. The force of the body pressure on the floor of the lift is 400 N. Determine the body weight.

Initial data: a (acceleration with which the lift moves up) = 1 m / s ^ 2; P (force of body pressure on the floor of the lift) = 400 N.

Constants: g (acceleration due to gravity) = 9.81 m / s ^ 2.

Let’s compose a formula for determining the body pressure on the floor of the elevator: P = ma + mg = m * (a + g).

Let us express and calculate the body mass: m = P / (a + g) = 400 / (1 + 9.81) = 400 / 10.81 = 37 kg.

Answer: Body weight is 37 kilograms.