The lifting capacity of the elevator is 2t. How many sheets of iron can be loaded
The lifting capacity of the elevator is 2t. How many sheets of iron can be loaded into the elevator if each sheet is 3 m long, 60 cm wide and 4 mm thick?
m = 2 t = 2000 kg.
l = 3 m.
a = 60 cm = 0.6 m.
h = 4 mm = 0.004 m.
ρ = 7800 kg / m ^ 3.
N -?
The lifting capacity of the elevator is 2 tons, which means that it can lift a load with a mass of m = 2 tons.
The number of sheets N that the elevator can lift is expressed by the formula: N = m / m1, where m1 is the mass of one sheet of iron.
We express the mass of one sheet m1 by the formula: m1 = ρ * V1, where ρ is the density of iron, V1 is the volume of one sheet.
Since the sheet has the shape of a rectangular parallelepiped, its volume V1 is expressed by the formula: V1 = l * a * h.
N = m / ρ * l * a * h.
N = 2000 kg / 7800 kg / m ^ 3 * 3 m * 0.6 m * 0.004 m = 35.6.
Answer: N = 35 whole sheets of iron can be immersed in the elevator.