The lifting capacity of the elevator is 3 tons. How many sheets of iron can be loaded into the elevator

The lifting capacity of the elevator is 3 tons. How many sheets of iron can be loaded into the elevator if each sheet is 3 m long, 60 cm wide and 4 mm thick?

Given: mload = 3 t = 3000 kg

a = 3 m; B = 60 cm = 0.6 m; s = 4 mm = 0.004 m, hw = 7800 kg / m3

In this problem, you need to find n – the number of iron sheets that can be loaded into an elevator, the carrying capacity of which is mload = 3000 kg

Solution: n = mload / m, where m is the mass of one sheet of iron.
m = pV = p * a * b * c
n = mload / p * a * b * c
= 3000 / (7800 * 3 * 0.6 * 0.004) = 53.4
Since we need the exact number of sheets, then, rounding down the answer, we get that 53 sheets of iron can be immersed in the elevator.