The light bulb is connected to a 110 V network. How much electricity has passed through the filament
| September 16, 2021 | education
The light bulb is connected to a 110 V network. How much electricity has passed through the filament of the lamp. If the current is 220 J?
Given:
U = 110 V
A = 220 Joules
Find:
q =? CL
Solution:
We use the basic formula: A = q * U (electric charge multiplied by voltage strength)
Hence it follows: q = A / U (Amperage divided by voltage)
q = 220/110 = 2 C (current divided by voltage)
q = 2 Cl
Answer: 2 Cl
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