The line intersects the sides of triangle ABC at points M and K, respectively, so that MK is parallel to AC, BM: AM = 1: 4.

The line intersects the sides of triangle ABC at points M and K, respectively, so that MK is parallel to AC, BM: AM = 1: 4. Find the perimeter of triangle BMK if the perimeter of triangle ABC is 25 cm.

The aspect ratio BM: AM is 1: 4. Let BM be equal to x, then AM = 4x. Since AB = BM + AM, then AB = x + 4x = 5x.

Consider the triangles BMC and ABC: angle B is common for both triangles, the angle of BMC is equal to the angle BAC (corresponding angles with parallel MK and AC and secant AB).

So triangles BMK and ABC are similar.

Let’s calculate the coefficient of similarity:

k = AB / BM = 5x / x = 5.

This means that the perimeters are 5 to 1.

P (ABC) / P (BMK) = 5.

25 / R (BMK) = 5.

P (BMK) = 25/5 = 5 (cm).

Answer: The perimeter of the IUD triangle is 5 cm.



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