The line passes through the origin and point A (3/7; 1/14). Find the formula of the function whose graph is this line.

If the straight line y = kx + b passes through the point O (x1; y1), then the following relation is true:

y1 = kx1 + b.

According to the condition of the problem, the straight line y = kx + b passes through the point O (0; 0), which is the origin, therefore, the following relation is true:

0 = k * 0 + b.

Consequently, the free term b in the equation of the straight line is 0.

It is also known that this line passes through the point A (3/7; 1/14), therefore, the following relation is true:

1/14 = k * (3/7).

From this ratio we get:

k = (1/14) / (3/7);

k = (1/14) * (7/3);

k = 1/6.

Therefore, the desired equation of the straight line:

y = x / 6.

Answer: the desired equation of the straight line y = x / 6.