The load is pulled along an inclined plane, applying a force of 100N in the direction of travel.

The load is pulled along an inclined plane, applying a force of 100N in the direction of travel. What is the efficiency of an inclined plane if the weight of the load is 30 kg, the length of the inclined plane is 3m, and the height is 0.5m?

F = 100 N.

m = 30 kg.

g = 10 m / s2.

h = 0.5 m.

S = 3 m.

Efficiency -?

The efficiency coefficient shows what part of the spent work Az, expressed as a percentage, goes into useful work Ap: Efficiency = Ap * 100% / Az.

Useful work when lifting a body along an inclined plane An is expressed by the formula: An = m * g * h, where m is the mass of the load, g is the acceleration of gravity, h is the height of the inclined plane.

The expended work Az is expressed by the formula: Az = F * S, where the force F with which the load is pulled, S is the length of the inclined plane.

The formula for determining the efficiency of an inclined plane will take the form: efficiency = m * g * h * 100% / F * S.

Efficiency = 30 kg * 10 m / s2 * 0.5 m * 100% / 100 N * 3 m = 50%.

Answer: this inclined plane has an efficiency of 50%.