The loaded trolley weighs 3 kN. What force is required for the uniform movement

The loaded trolley weighs 3 kN. What force is required for the uniform movement of the trolley if the friction force is 0.005 of the trolley weight with the load?

Initial data: P (trolley weight with load) = 3 kN = 3 * 10 ^ 3 N = N (support reaction force); μ (coefficient of friction) = 0.005.

Since the movement of the trolley must be uniform, the following relation will be true: m * a = 0 = F – Ffr, whence F = Ffr = μ * N = μ * P.

Let’s perform the calculation: F = 0.005 * 3 * 10 ^ 3 = 15 N.

Answer: For uniform movement of the trolley, a force of 15 N.