The locomotive is driving a train of 10 cars. The force of resistance to movement of each of the cars is 40 kN

The locomotive is driving a train of 10 cars. The force of resistance to movement of each of the cars is 40 kN, and of the locomotive is 50 kN. The traction force developed by the locomotive is 450 kN. Determine the resultant of these forces. What can be said about the nature of the movement of the train?

Movement resistance force:

Fс = n * F1 + F2, where n is the number of cars (n = 10), F1 is the force of resistance to the movement of the car (F1 = 40 kN), F2 is the force of resistance to the movement of the locomotive (F2 = 50 kN).

Fc. = 10 * 40 + 50 = 450 kN.

Resultant forces: F = Ft – Fc, where Ft is the traction force of the locomotive (Ft = 450 kN).

F = 450 – 450 = 0.

Since the forces are mutually balanced, then, according to Newton’s first law, the rolling stock is either at rest, or moves straight and uniformly.