The locomotive starts off the platform, what speed does the train gain after 1 km, if the acceleration of the train is 0.05 m / s2

These tasks: V0 (initial speed) = 0 m / s (the considered locomotive was moving away); S (distance traveled) = 1 km (SI S = 1000 m); a (acceleration) = 0.05 m / s2.

The speed that the locomotive under consideration will acquire after 1 km can be expressed from the formula: S = (V ^ 2 – V0 ^ 2) / 2a = (V ^ 2 – 0) / 2a, whence V = √ (2a * S).

Let’s calculate: V = √ (2 * 0.05 * 1000) = 10 m / s.

Answer: After passing 1 km, the locomotive in question will have a speed of 10 m / s.