The machine fires 600 bullets per minute. The mass of each bullet is m = 4 g
The machine fires 600 bullets per minute. The mass of each bullet is m = 4 g, its initial velocity is v = 500 m / s. Find the average force of recoil when shooting.
The force acting on the bullet Fп is equal to the recoil force taken with the opposite sign Fo: Fп = -Fo. That is, to find the absolute value of the recoil force, it is enough to find the force acting on the bullet.
Consider a time interval equal to the duration of one bullet: T = 60 s / 600 = 0.1 s.
The rest of the time, the process is repeated and does not change the overall result.
For this time interval, we will write Newton’s second law in the form in which the change in the momentum of the bullet during the time T under the action of the force Fp of the powder gases appears.
F = m (Vк-Vн) / T,
where Fp is the force acting on the bullet, m is the mass of the bullet, Vk = 500 m / s is the speed of the bullet after it leaves the barrel, Vn = 0 is the initial velocity of the bullet, T is the time interval between shots.
F = (0.004 kg * (500 m / s -0 m / s)) / 0.1 s = 20 kg * m / 0.1 s = 20 N.
Answer: 20 N.