The machine is designed for the carriage of cargo weighing 3 tons. How many sheets of iron can be loaded

The machine is designed for the carriage of cargo weighing 3 tons. How many sheets of iron can be loaded on it if the length of each sheet is 2m, width is 80cm and thickness is 2mm, iron is 7800kg \ m3 7.8g \ m3.

M = 3 tons = 3000 kilograms – the mass of the cargo the car is designed to carry;

a = 2 meters – the length of the iron sheet;

b = 80 centimeters = 0.8 meters – the width of the iron sheet;

c = 2 millimeters = 0.002 meters – the thickness of the iron sheet;

ro = 7800 kg / m3 – iron density.

It is required to determine n – how many iron sheets can be loaded into a car.

Let’s find the volume of one iron sheet:

V = a * b * c = 2 * 0.8 * 0.002 = 0.0032 m3.

Then the mass of one iron sheet will be equal to:

m = V * ro = 0.0032 * 7800 = 24.96 kilograms.

The number of sheets will be equal to:

n = M / m = 3000 / 24.96 = 120.2.

Since, according to the condition of the problem, n must be an integer, we round up to 120.

Answer: 120 sheets can be loaded on the machine.