The magnetic flux through a closed conductor with an electrical resistance of 2 ohms increased uniformly

The magnetic flux through a closed conductor with an electrical resistance of 2 ohms increased uniformly from 0.2 mWb to 0.5 mWb. How much charge has passed through the cross section of the conductor?

To find out the required amount of charge, we will use the formula: | q | = ΔФ / R = (Ф2 – Ф1) / R, where Ф2 is the increased magnetic flux (Ф2 = 0.5 mVb = 0.5 * 10-3 Wb); F1 – initial magnetic flux (F1 = 0.2 mVb = 0.2 * 10-3 Vb); R is the resistance of the taken closed conductor (R = 2 ohms).

Let’s calculate: | q | = (F2 – F1) / R = (0.5 * 10-3 – 0.2 * 10-3) / 2 = 0.15 * 10-3 Cl.

Answer: A charge in the amount of 0.15 mC should have passed through the taken closed conductor.