The magnetic flux through a conductive ring with a resistance of 5 Ohm increased uniformly by 10 Wb in 2 s.

The magnetic flux through a conductive ring with a resistance of 5 Ohm increased uniformly by 10 Wb in 2 s. What charge has flowed through the ring during this time?

To find out the charge passed in 2 s through the indicated conducting ring, we use the formula: qx = ΔF / R, where ΔF is a known change (increase) in the magnetic flux (ΔF = 10 Wb); R is the resistance of the specified conductive ring (R = 5 ohms).

Let’s perform the calculation: qx = ΔF / R = 10/5 = 2 Cl.

Answer: For 2 s, a charge of 2 C passed through the indicated conducting ring.