The magnitude of one of the angles of a triangle is 20 degrees. The magnitude of the acute angle between

The magnitude of one of the angles of a triangle is 20 degrees. The magnitude of the acute angle between the bisectors of the other two angles of this triangle is.

The sum of the inner angles of the triangle is 180, then the sum of the angles (ABC + ACB) = (180 – BAC) = (180 – 20) = 160.

Since ВM and CК are the bisectors of angles B and C, then the angle OBC = ABC / 2, ygo OCB = AСB / 2.

Then the sum of the angles OBC + OCB = (ABC + ACB) / 2 = 160/2 = 80.

Angle BOC = (180 – OBC – OCB) = 180 – 80 = 100.

Answer: The angle between the bisectors is 100.