The magnitude of one of the angles of an isosceles triangle is 70 degrees find the angles of this triangle

In the equal. △ -ke angles at the base are equal.

Let’s consider 2 cases.

1) So, the angle at the apex △ -ka is 70 °, then at the base the angles add up to:

180 ° – 70 ° = 110 °.

Each base angle will be 110 °: 2 = 55 °.

2) Suppose that the angle at the base of p / b △ -ka is known, namely – 70 °.

Find the angle at the vertex.

180 ° – 2 * 70 ° = 180 ° – 140 ° = 40 °.

Answer: 1) 70 °, 55 °, 55 °; 2) 40 °, 70 °, 70 °.