The mass and gravity acting on a person, if he drinks 0.2 liters of water, will increase accordingly by

The mass and gravity acting on a person, if he drinks 0.2 liters of water, will increase accordingly by a) 2 kg 19.6 N b) 0.2 kg 19.6 N c) 0.2 kg 1.96 N?

Given:

V = 0.2 liters = 0.2 dm3 (cubic decimeters) – the volume of water that a person has drunk;

ro = 1000 kg / m3 (kilogram per cubic meter) – density of water.

It is required to determine how much the mass and gravity acting on a person will increase after he drinks water.

Let’s translate the units of measurement of volume in the SI system:

V = 0.2 dm3 = 0.2 * 10-3 m3 (cubic meter).

Then, the mass of water you drink will be equal to:

m = ro * V = 1000 * 0.2 * 10-3 = 0.2 kilograms.

The force of gravity will increase by an amount equal to:

F = m * g (where g = 9.8 Newton / kilogram);

F = 0.2 * 9.8 = 1.96 Newton.

Answer: the mass of a person will increase by 0.2 kilograms, the force of gravity by 1.96 Newton