The mass fraction of calcium chloride in the solution obtained by mixing 300 g of a solution with a mass fraction

The mass fraction of calcium chloride in the solution obtained by mixing 300 g of a solution with a mass fraction of 15% CaCl2 and 200 g of a solution with a mass fraction of 2.5% CaCl2 is …

1. Find the masses of salts in solutions, and then add them:

m1 (CaCl2) = (m (solution) * ω (CaCl2)) / 100% = (300 g * 15%) / 100% = 45 g.

m2 (CaCl2) = (m (solution) * ω (CaCl2)) / 100% = (200 g * 2.5%) / 100% = 5 g.

mtotal (CaCl2) = m1 (CaCl2) + m2 (CaCl2) = 45 g + 5 g = 50 g.

2. Find the mass of the final solution:

m final (solution) = m1 (solution) + m2 (solution) = 300 g + 200 g.

3. Find the final mass fraction of salt:

ω final (CaCl2) = (m (CaCl2) / m (solution)) * 100% = (50 g / 500 g) * 100% = 10%.

Answer: ω final (CaCl2) = 10%.