The mass fraction of carbon is 54.54 mass fraction of hydrogen 9.09 mass fraction of oxygen 36.36
The mass fraction of carbon is 54.54 mass fraction of hydrogen 9.09 mass fraction of oxygen 36.36 oxygen density 1.345 Find the formula.
Let’s take the mass of hydrocarbon per 100 g.
Let’s find the mass of hydrogen in the hydrocarbon.
100 g – 100%,
m (H) – 9.09%.
m = (100 g × 9.09%): 100% = 9.09 g.
Let’s find the mass of carbon.
100 g – 100%,
m (C) – 54.54%.
m = (100 g × 54.54%): 100% = 54.54 g.
Let’s find the mass of oxygen.
100 g – 100%,
m (O) – 36.36%.
m = (100 g × 36.36%): 100% = 36.36 g.
Let’s find the amount of matter of atoms in the compound.
n = m: M.
n (H) = 9.09: 1 = 9.09 mol.
n (C) = 54.54: 12 = 4.55 mol.
n (O) = 36.36: 16 = 2.27 mol.
We find the ratio of the amounts of substances.
n (C): n (H): n (O) = 4.55: 9.09: 2.27 = 2: 4: 1.
Let’s find the molar mass of the hydrocarbon.
D (O2) = 1.345 × 32 = 43.
The formula for the C2H4O hydrocarbon is ethanal.
M (C2H4O) = 12 × 2+ 4 + 16 = 44 g / mol.