The mass fraction of Ferum in the oxide is 70%. Determine the oxide formula. In the answer, indicate the sum of the indices.

Fe2O3-iron oxide (|||)
molecular weight – 56 + 56 + 16 + 16 + 16 = 160
iron mass – 56 + 56 = 112
112: 160 * 100% = 70%
sum of indices – 2 + 3 = 5



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