The mass fraction of oxygen in the saturated monohydric alcohol is 18.18% Determine the molecular formula of the alcohol.

Let’s write down the data: R – OH (alcohol)
W (O) = 18.18%

Determine the formula: CxHyOz -?

We find the amount of oxygen:
Y (O) = 18.18 / 16 = 1.14 mol

Based on the general formula for limiting monohydric alcohols, we make calculations:
CnH2n + 1OH;

Mr (CxHyOz) = 100 p.h .;

CnH2n + 1OH = 100;

12n + 2n + 1 + 16 + 1 = 100;

14n = 100-18;

14n = 82;

n = 5 8 = 6

Let’s establish the formula: С6Н13ОН – hexanol.

Answer: С6Н13ОН – hexanol.