The mass fraction of sulfur in iron sulfate (3) Fe2 (SO4) 3 is equal to ..?

Given:
Fe2 (SO4) 3

To find:
ω (S in Fe2 (SO4) 3) -?

1) ω (S in Fe2 (SO4) 3) = N (S in Fe2 (SO4) 3) * Ar (S) * 100% / Mr (Fe2 (SO4) 3) = 3 * 32 * 100% / 400 = 24%.

Answer: Mass fraction of S in Fe2 (SO4) 3 is 24%.



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