The mass fraction of sulfur in its combination with iron is 36%. Determine the mass of iron

The mass fraction of sulfur in its combination with iron is 36%. Determine the mass of iron contained in 50 g of the compound.

Given:

m (compounds) = 50 g,

w (S) = 36%

m (Fe) -?

Solution:

1 Find the mass of sulfur in the compound.

50 g – 100%,

m g (S) – 36%.

m g (S) = (50 g × 36%): 100% = 18 g.

2. Find the mass of iron in the compound.

50 g – 18 g = 32 g.

Second option.

100% – 36% = 64% (iron).

50 g -100%,

x – 64%,

x = (50g × 64%): 100% = 32g.

Answer: 32 g of iron.