The mass of 0.2 mol of calcium carbonate CaCO3 is …

Given:
n (CaCO3) = 0.2 mol

To find:
m (CaCO3) -?

Decision:
1) Using the periodic system of D.I.Mendeleev, calculate the molar mass of calcium carbonate, which will be numerically equal to the relative molecular mass:
M (CaCO3) = Mr (CaCO3) = Ar (Ca) + Ar (C) + Ar (O) * 3 = 40 + 12 + 16 * 3 = 100 g / mol;
2) Calculate the mass of calcium carbonate:
m (CaCO3) = n (CaCO3) * M (CaCO3) = 0.2 * 100 = 20 g.

Answer: The mass of calcium carbonate is 20 g.



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