The mass of 1 iron atom is …

1. Let’s calculate the chemical amount of an iron atom using Avogadro’s constant:

n (Fe) = N (Fe): Na = 1: (6.02 * 10 ^ 3) = 1.66 * 10 ^ -24 mol;

2.Calculate the mass of the iron atom:

ma (Fe) = n (Fe) * Ar (Fe) = 1.66 * 10 ^ -24 * 56 = 92.96 * 10 ^ -24 = 9.296 * 10 ^ -23 g.

Answer: 9.296 * 10 ^ -23 g.



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